Allan87 - 15-8-2008 at 09:47
XeO2F2
Xe = 5s2 4d10 5p6 which contributes 8
F2 contributes 2
O2 contributes 4?
The_Davster - 15-8-2008 at 10:02
What exactly are you asking?
Allan87 - 15-8-2008 at 10:03
whether oxygen contributes 4 or not
JohnWW - 16-8-2008 at 08:31
Yes, it would contribute 4 electrons, to give the Xe(VI) oxyfluoride, with a lone pair of electrons left on the Xe (which can be utilized by reaction
with O3 or atomic oxygen to give a Xe(VIII) oxyfluoride, XeO3F2), and a total of 14 valence electrons on Xe, some of which occupy formerly empty 5d
and possibly 4f orbitals.