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Allan87
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[*] posted on 15-8-2008 at 09:47
VSEPR

XeO2F2

Xe = 5s2 4d10 5p6 which contributes 8
F2 contributes 2
O2 contributes 4?
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The_Davster
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[*] posted on 15-8-2008 at 10:02


What exactly are you asking?



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Allan87
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[*] posted on 15-8-2008 at 10:03


whether oxygen contributes 4 or not
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JohnWW
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[*] posted on 16-8-2008 at 08:31


Yes, it would contribute 4 electrons, to give the Xe(VI) oxyfluoride, with a lone pair of electrons left on the Xe (which can be utilized by reaction with O3 or atomic oxygen to give a Xe(VIII) oxyfluoride, XeO3F2), and a total of 14 valence electrons on Xe, some of which occupy formerly empty 5d and possibly 4f orbitals.
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