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Author: Subject: Stereochemistry: Racemic Acid + Alcohol
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[*] posted on 23-2-2017 at 12:41
Stereochemistry: Racemic Acid + Alcohol

Came across this question:
"An excess of the racemic acid CH3CHClCOOH is allowed to react with (S)-2-methyl-1-butanol to form the ester, CH3CHC(=O)OCH2CH(CH3)CH2CH3, and the reaction mixture is carefully distilled. Three fractions are obtained, each of which is optically active. Draw stereochemical formulas of the compound or compounds making up each fraction."

I got the following 2 products, but wasn't completely sure about the third.

Any suggestions? Thanks.

Stereochemistry 1.png - 3kB
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