crazyheaven
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Oxidation- Reduction
What happens if MnO2 was mixed with KI and 9M sulfuric acid?
Can't seem to figure this one out.
[Edited on 6-8-2008 by crazyheaven]
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woelen
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The MnO2 will oxidize the iodide to iodine:
MnO2 + 4H(+) + 2I(-) --> Mn(2+) + I2 + 2H2O
At a concentration of 9M for the sulphuric acid, I also can imagine that the acid itself may be oxidizing the iodide to some extent as well, making
the reaction less clean (production of sulphur, hydrogen sulfide and sulphur dioxide). I would suggest to decrease the concentration of the acid to 4M
or something like that. At such a lower concentration the only reaction will be the one, given above.
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crazyheaven
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Thank you for the help. Didn't think I'd get such a fast reply.
Seems I would be able to learn a lot from this site.
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