Sciencemadness Discussion Board
Not logged in [Login ]
Search the forums Search   Frequently Asked Questions FAQ   View member list Member List   Today's Posts Today's Posts   Forum Stats Stats Back to: sciencemadness.org
Sciencemadness Discussion Board » Fundamentals » Beginnings » labile hydrogen/deuterium exchange Go To Bottom

Printable Version  
Author: Subject: labile hydrogen/deuterium exchange
madd
Harmless
*



Posts: 1
Registered: 5-1-2013
Member Is Offline

Mood: No Mood

[*] posted on 16-3-2014 at 12:30
labile hydrogen/deuterium exchange

Hi all,
Say I have a compound which has a single labile hydrogen and I want to substitute that hydrogen for deuterium. Say I have my compound inside sealed dialysis tubing and that tubing is set inside a solution of D2O. How can I calculate what fraction of my compound will be deuterated at equilibrium?

The mL quantity of compound and D2O are known. And KH/KD (kinetic isotope effect) is known. My first guess is that VD=VH * KD/KH.

Am I on the right track?

[Edited on 16-3-2014 by madd]

[Edited on 16-3-2014 by madd]
View user's profile View All Posts By User

 Sciencemadness Discussion Board » Fundamentals » Beginnings » labile hydrogen/deuterium exchange   Go To Top