RedsAreRaw - 23-2-2017 at 12:41
Came across this question:
"An excess of the racemic acid CH3CHClCOOH is allowed to react with (S)-2-methyl-1-butanol to form the ester,
CH3CHC(=O)OCH2CH(CH3)CH2CH3, and the reaction mixture is carefully distilled. Three fractions
are obtained, each of which is optically active. Draw stereochemical formulas of the compound or compounds making up each fraction."
I got the following 2 products, but wasn't completely sure about the third.
Any suggestions? Thanks.
