CHRIS25 - 8-5-2012 at 13:06
Citric Acid:
Molar mass is 192g/mole anhydrous
Solubility = 72grams per 100mL
19.2grams per 100mL = 1mole
Therefore does that mean that maximum concentration of citric acid that can be made would be a 3.75 mole because of its solubility limit (72 divided
by 19.2)?
Am I confused?
Hexavalent - 8-5-2012 at 13:14
What are you trying to do? Calculate the concentration of a saturated solution of citric acid?
If so, then yes . .
If so, then solubility = 720g/L
Moles = Mass/Mr
720/192 = 3.75 moles.
3.75/10 = 0.375
Therefore, 1L of a saturated solution of citric acid will hold 3.75 moles of citric acid, or 720g.
Therefore, 100ml of a saturated solution of citric acid will hold 0.375 moles of citric acid, or 72g.
Thus, the maximum concentration for a solution of citric acid (I presume your solubility data refers to RTP) will be 3.75 molar.
[Edited on 8-5-2012 by Hexavalent]
CHRIS25 - 8-5-2012 at 13:31
Hi Hexavalent, yes that was it. At least I am on the right road here.
Hexavalent - 8-5-2012 at 13:34
Yes, you certainly are.
This might be better BTW in the 'Short questions thread', I've sent the mods a message to let them know. Might be better there than having an entire
thread on its own.
CHRIS25 - 8-5-2012 at 13:45
Sorry, did not know there was a short questions thread, can't seem to find it.
Hexavalent - 8-5-2012 at 13:49
http://www.sciencemadness.org/talk/viewthread.php?tid=14239