Originally posted by Organikum
Some stuff from the-hive and an old patent:
Quote: |
Toluene to Benzaldehyde by Manganesepersulfate
by: neograviton
(edited by me)
Here is a easy way to do it with Mn(V)sulfate. A way I used many time!
First get some MnO2. You can buy it as "Manganese-Black" a pigment for cement and concrete. Thats about 70% MnO2. Then put it in an equimolar amount
of H2SO4 (100%) and heat it up. Make it really hot. (>200°C). Let it be there for about half an hour. When I do this, I let The acid become so
hot, that white steam comes out. After that, let it cool down. You just have made Mn(V)SO4. It is soluble in 37% H2SO4 (battery acid) with a deep,
chocolate like brown color.
After that put it 1:1 with the toluene in about 60% H2SO4 (enough H2SO4, so that nearly everything dissolves). Heat (or cool) it to about 50-60°C and
stirr it well. After 3-4 hours you will have mostly Benzaldehyd (in my cases about 70%)
Distill the Benzaldehyd/Toluene out by a simple steam distillation. (Just boil water out, until there is no oily layer any more)
When you start boiling that stuff, the color of the liquid becomes sand-like. Thats because the rest of the Mn(V)SO4 breaks down to Mn(II)SO4.
And now the best: just put the liquid in a electrolytic cell (in the anode-part) and put some electricity through it, while stirring. The color will
chance to chocolate brown once again, and you can use it again!!! About 6 times!
|
Hi, I am trying to work out the ratios for this reaction. Perhaps I am confused with the term equimolar. Disregarding the 70% for now. Mn02 is
86.9gmol-1 The acid at 98% with a specific gravity of 1.84gml-1 making it 1840gL-1 therefore 1840/98 = 18.7molL-1. So if I was to use 10g of the Mn02
which is 0.11 moles, (10/86.9 = 0.11 then how much acid should I add for this amount, surely it is not the same amount of moles, for if it was it
would come to a dismal aprox 6ml. This cannot be right, and I am obviously missing something very important. I was reading this, and am not ready to
do this reaction, but it didn't make sence and I thought I would queerie the instructions. Perhaps this is a beginners question and belongs in that
area, It obviously isn't a begginers procedure. I am wondering also if others have indeed followed this route for the production of this compound.
|