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Author: Subject: EtOH + (CH3)2CO > ?
Acuyo
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[*] posted on 5-3-2017 at 16:04
EtOH + (CH3)2CO > ?


Can someone tell me what the likely product of an excess of equal parts water and acetone; and then about equal "denatured alcohol" ethanol under heat (~60c)would be? Mildly acidic conditions, probably PH 5.5 - 6.

The ethanol was a mistake and a very distinct odor was apparent, not sure what was created, I assume it's the product of (CH3)2CO and EtOH, but that's exactly an assumption and I can't add atoms yet.

thx?
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DraconicAcid
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[*] posted on 5-3-2017 at 16:05


Acetone will not react with ethanol, even with mild acid and mild heat.



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Acuyo
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[*] posted on 5-3-2017 at 16:11


how about methanol?

same?

[Edited on 6-3-2017 by Acuyo]
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gluon47
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[*] posted on 5-3-2017 at 20:15


This almost certainly didn't happen in your case, but under the right conditions, acetone and ethanol do reversibly react to form a hemiacetal/acetal. An acid catalyst and some way to remove the water and drive the equilibrium forward are needed.

C2H5OH + (CH3)2CO ==> (CH3)2C(OC2H5)OH

2 ROH + (CH3)2CO <==> (CH3)2C(OC2H5)2 + H2O

I actually tried this reaction out a while ago in the hope of isolating the acetal product, Diethoxymethane. All I got was a thick yellowish liquid with a distinct pleasant smell that I cannot remember in detail.




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