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mycotheologist
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[*] posted on 22-5-2012 at 05:38
Stannous Halides - Are they all reducing agents?

I'm aware that stannous chloride is commonly used as a selective reducing agent for reducing nitro groups to amino groups. Has anyone experimented with stannous bromide or stannous iodide for this purpose?
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UKnowNotWatUDo
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[*] posted on 22-5-2012 at 05:57


I know tin(II) bromide is indeed a reducing agent as well. I assume it will also reduce nitro compounds to amines but this is just an assumption. Obviously the easiest way to find out would be to spend some time googling or running some tests. Stannous bromide is easily prepared from powdered tin metal and hydrobromic acid.
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mycotheologist
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[*] posted on 22-5-2012 at 06:04


Yeah I'm gonna prepare some since I have some 40% HBr lying around. Rather than powdered tin, I'll just use tin wire (lead free solder). Couldn't find any info on the reducing agent properties of SnBr2 on google.
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[*] posted on 22-5-2012 at 06:12


I suspect that they would as would all the other tin II salts.
The reducing property is due to the tin II ion, I doubt that the anion would have much effect.
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[*] posted on 23-5-2012 at 19:33


Speaking of stannous chloride, does anyone have any detailed reaction mechanisms for the reductions?
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[*] posted on 23-5-2012 at 23:23


The anion does have some effect, due to different complex formation properties. The redox properties of metals and their ions can be greatly affected by the anions to which they are coordinated. I do not know the exact properties of the tin-complexes, but if you are researching reducing properties of tin(II) salts, then also take into account the coordinating properties of the anion.



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