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greenlight
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Quote: Originally posted by underground  | Just a quick question.
Will 2 grams of "X" explosive, with lets assume its VoD is 4000m/s, have the same power or about the same power as 1 gram of "Z" explosive with VoD
8000m/s ?
[Edited on 27-1-2018 by underground] |
Theoretically, Z would be twice as good especially having more shattering power (brisance). Explosives with VOD 4000m/s and below have more of a
pushing and heaving effect while the high VOD explosives have more of a shattering and fragmenting effect on objects they are in contact with so they
really are two separate cases.
Realistically, differences in flame temperature, heat of explosion, brisance, oxygen balance, theoretical max density, etc, between the two explosives
would also come into play so it quickly becomes complicated.
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Morgan
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Any suggestions of where to buy a filtered high voltage DC power supply something around 20-30,000 volts and 1 milliamp or so?
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Rocinante
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The shattering effect on steel targets will be about an order of magnitude higher (5-10×) with 8000 m/s explosive than with 4000 m/s. Not sure about
2 g amounts, though. You're talking the difference between high end PETN/ETN and EGDN/NC plastic and melt cast ETN (250 - 300 kbar) and slightly more
powerful ammonals or pressed primary explosives like TATP (~ 50 kbar). Most inert/RDX/PETN/ETN plastics made at home will likely max out in the 7700
m/s range.
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greenlight
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Your correct about the PE's with inerts.
I use PETN plastic with about 15% binder and plasticizer with density @ 1.44 and I calculate VOD to be around the 7000m/s mark.
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Rosco Bodine
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@ nitro-genes
Some more thought has been given to the reduction in alkaline condition and has led me to consider a system using Magnesium based salts.
Magnesium hydroxide in water has a solution pH of 10.3.
Glycine will inhibit precipitation of Manganese hydroxide in an alkaline system up to about a pH of 10. So I am thinking a reduction of magnesium
picrate or perhaps sodium picrate could be done using magnesium ascorbate. A manganous glycinate salt could be used as the reducing catalyst, with an
additonal molar equivalent of glycine added to be available to neutralize the manganese +III and form the transient manganese + III (tris) glycinate
from the oxidized manganous + II (bis) glycinate.
Whether this buffering scheme works will depend on the ability of the soluble glycine chelated manganese to still be useful as a reducing agent that
can be recycled back to the +II form by reacting with the gradually added magnesium ascorbate.
In the alternative it may be that no reduction catalyst is needed if the magnesium ascorbate is found to be active in reducing magnesium picrate or
perhaps basic magnesium picrate directly.
The manganous biglycinate would form in situ via double decomposition of manganous sulfate and magnesium biglycinate
These reagents are OTC nutritional supplement items
https://www.vitacost.com/now-foods-magnesium-biglycinate-pow...
https://www.vitacost.com/now-foods-magnesium-ascorbate-powde...
https://www.vitacost.com/now-foods-glycine-pure-powder
https://www.vitacost.com/now-foods-magnesium-oxide-pure-powd...
https://www.vitacost.com/phillips-genuine-milk-of-magnesia-s...
[Edited on 1/30/2018 by Rosco Bodine]
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underground
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Anyone who has already tried to make both ETN and PETN, which one can easier be nitrated ?
[Edited on 3-2-2018 by underground]
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Laboratory of Liptakov
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PETN is easily steps , faster steps and yields are better on the weight fo acids. Almost 2x more advantageous.
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underground
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So there is no point of wasting chemicals making ETN while PETN have better yields and more power. The only disadvantage is the P. price compare to E.
[Edited on 3-2-2018 by underground]
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Bert
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In USA, you can buy pure erythritol as a diet sweetener by the pound, no questions asked. Pentaerythritol is harder to find.
Looking at the industrial manufacturing processes and base materials involved, I would THINK PETN should be the cheaper chemical in bulk?
[Edited on 4-2-2018 by Bert]
Rapopart’s Rules for critical commentary:
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2. List any points of agreement (especially if they are not matters of general or widespread agreement).
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joseph6355
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| Quote: Originally posted by Bert | In USA, you can buy pure erythritol as a diet sweetener by the pound, no questions asked. Pentaerythritol is harder to find.
Looking at the industrial manufacturing processes and base materials involved, I would THINK PETN should be the cheaper chemical in bulk?
[Edited on 4-2-2018 by Bert] |
True. There is no substantial use for PE that would justify it being sold OTC.
Sure, it has its uses besides energetics, but a common person would never need it. Erythritol on the other hand is the new mainstream sweetener that
everybody wants.
The problem with synthesizing ETN is that it takes big amounts of nitric acid to fully nitrate, and using nitrating salts makes a mess, forcing you to
add more sulfuric acid in order to dissolve it and allow you to add the rest of the salt. Not to mention that the yield gets very compromised when
using nitrating salts.
[Edited on 4/2/18 by joseph6355]
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greenlight
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I personally prefer PETN synthesized with 70% nitric and recrystallised from acetone. Very smooth noyration with good yields.
I think whatever is more convenient is better they both end up with four nitrate ester groups.
The only real differences I can think of is that the ETN is slightly more sensitive I have read.
PETN has a very small critical diameter hence its use in detcord I think.
ETN has a positive oxygen balance to consume binders if used in specialty compositions.
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joseph6355
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| Quote: Originally posted by greenlight | I personally prefer PETN synthesized with 70% nitric and recrystallised from acetone. Very smooth noyration with good yields.
I think whatever is more convenient is better they both end up with four nitrate ester groups.
The only real differences I can think of is that the ETN is slightly more sensitive I have read.
PETN has a very small critical diameter hence its use in detcord I think.
ETN has a positive oxygen balance to consume binders if used in specialty compositions.
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ETN has about 2/3 of the friction sensitivity of PETN. I think that if it was plasticized, it would improve its safety greatly.
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greenlight
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Yes, the inert lubricating effects would definitely reduce the sensitivity and make for safer handling..
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underground
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Due to ETN's positive OB, woult it be a better option with plasticizer than PETN ?
| Quote: Originally posted by joseph6355 |
The problem with synthesizing ETN is that it takes big amounts of nitric acid to fully nitrate, and using nitrating salts makes a mess, forcing you to
add more sulfuric acid in order to dissolve it and allow you to add the rest of the salt. Not to mention that the yield gets very compromised when
using nitrating salts.
[Edited on 4/2/18 by joseph6355] |
Whenever tried to dissolve E into SA, yields goes down. Looks like it works better by just adding it as a very fine powder into the mixture.
[Edited on 4-2-2018 by underground]
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Laboratory of Liptakov
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Of course. Very dry E in very powder form is base for adding to Acids. For high yield. His sale distribution form is wet. Against it, PE is possible
in first step dissolve in HNO3 65 (humidity is unimportant) and instantly after disolving adding as the drop into H2SO4 95. Yields are maximal.
Adding E in same method is yield zero.
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greenlight
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I don't think you would notice much difference between PETN and ETN plastic explosive but yeah, the ETN has a little left over oxygen to give out
which could go to combustible binders/plasticizers.
PETN is not that oxygen deficient (-10%) anyway.
I would have to get out the calculator to find OB% ETN and it is late at night (will do it tomorrow).
I don't think it will be that large of a number.
[Edited on 4-2-2018 by greenlight]
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Hennig Brand
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Putty explosives are generally for shattering, but of course are good for anything, PETN putties are superior for this by at least 10% IIRC. If you
are using your plastic explosive to remove stumps the extra oxygen from ETN might be more useful, but that would be quite a waste of an expensive
explosive. This has been discussed a lot earlier in this thread, it is so long now I would need to search. The oxygen fuel reactions are much slower
and don't add much of anything to the shattering effect, it is about proximity of the atoms, density. Molecular explosives are more powerful because
the mixing is uniform, atoms close together.
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Laboratory of Liptakov
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ETN has OB + 5,3 Better than PETN OB - 10. PIB - 342,2 OIL - 345. (calc. on CO2 )
ETN + 10% binder = OB - 29,59. PETN + 10% binder = OB - 43,36
[Edited on 4-2-2018 by Laboratory of Liptakov]
Attachment: OB 4.0en.rar (283kB)
This file has been downloaded 458 times
[Edited on 4-2-2018 by Laboratory of Liptakov]
Development of primarily - secondary substances CHP (2015) Lithex (2022) Brightelite (2023) Nitrocelite and KC primer (2024)
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greenlight
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Hennig brand is right, you would get performance increase by mixing an oxygen deficient explosive with an oxygen rich explosive to bring the balance
closer to zero (like TNT and ammonium nitrate in ammatol).
The extra oxygen combined with something combustible like binders, plasticizers will just create an afterburn efect and a slightly more visible
fireball.
The ETN would be better than PETN if you using metal powder as a fuel to create a slight thermobaric effect.
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joseph6355
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Since you guys are talking about oxygen balance, I would like to know how to do the math and come up with an answer on how much N2, H2O and CO2 would
be generated from the decomposition of the explosive material, like this guy on this thread: http://www.sciencemadness.org/talk/viewthread.php?tid=9201#p...
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greenlight
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Here is one way I have learnt of calculating OB that works for CHNO explosives:
OB% = 1600 ÷ molecular wt of explosive [o - (2c + h/2)]
o is oxygen, c is carbon and h represents hydrogen.
If the end result is negative, the explosive is underoxidized and the reverse os true for a positive number.
Heres two examples:
RDX ; C3H6N6O6
Carbon = 3 × 12.01
Hydrogen = 6 × 1.008
Nitrogen = 6 × 14.008
Oxygen = 6 × 16.00
Total molecular weight RDX = 222.126
OB = 6 - (2×3) - (6÷2) = -3 × 1600 ÷ 222.126 = -21.61% for RDX (underoxidized)
PETN ; C5H8N4O12
Molecular weight PETN = (12.01×5) + (1.008×8) + (14.008×4) + (16.00×12) = 316.145
OB = 12 - (2×5) - (8÷2) = -2 × 1600 ÷ 316.145 = -10.12% for PETN ( underoxidized)
Explosives with a balance of 0 or slightly overoxidized are good. TNT is a good explosive because of its melt casting ability and good VOD but it is
severely underoxidized with a lot of excess carbon and carbon monoxide unused. This is why there is a noticeably black cloud of detonation products
with TNT.
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greenlight
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I just noticed you asked how to predict how much products will result from a detonation of a certain explosive. There is a set of rules for this for
CHNO explosives I have taken from explosives engineering (Cooper).
1. All the nitrogen forms N2.
2. All the hydrogen is burned to H2O.
3. Any oxygen left after H2O formation burns carbon to CO.
4. Any oxygen left after CO formation burns CO to CO2.
5. Any oxygen left after CO2 formation forms O2.
6. Traces of NOx are always formed.
Here is the example for RDX;
C3H6N6O6 > 3C + 6H + 6N + 6O
a. 6N > 3 N2
b. 6H + 3O > 3H2O (3 O remaining)
c. 3C + 3O > 3CO (all the O is used up now and no CO2 is formed)
C3H6N6O6 > 3H2O + 3CO + 3N2
There is CO remaining which proved the OB equation on the last post that RDX is underoxidized.
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joseph6355
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| Quote: Originally posted by greenlight | I just noticed you asked how to predict how much products will result from a detonation of a certain explosive. There is a set of rules for this for
CHNO explosives I have taken from explosives engineering (Cooper).
1. All the nitrogen forms N2.
2. All the hydrogen is burned to H2O.
3. Any oxygen left after H2O formation burns carbon to CO.
4. Any oxygen left after CO formation burns CO to CO2.
5. Any oxygen left after CO2 formation forms O2.
6. Traces of NOx are always formed.
Here is the example for RDX;
C3H6N6O6 > 3C + 6H + 6N + 6O
a. 6N > 3 N2
b. 6H + 3O > 3H2O (3 O remaining)
c. 3C + 3O > 3CO (all the O is used up now and no CO2 is formed)
C3H6N6O6 > 3H2O + 3CO + 3N2
There is CO remaining which proved the OB equation on the last post that RDX is underoxidized.
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Seems pretty easy.
How would the carbon fully oxidize?
If its not too much to ask, can you give me examples of some oxidizers and fuels? I know that aluminum can be used as a fuel, and ammonium nitrate as
an oxidizer (because it is OB+). What other EM can I use as fuel or oxygen sources?
[Edited on 8/2/18 by joseph6355]
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Bert
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| Quote: | | What other EM can I use as fuel or oxygen sources? |
Answered litteraly, that's going to be a very long list. Would this be an acceptable re statement, more or less meeting the intent of your question?
| Quote: | | Which single chemicals, themselves capable of being detonated have been COMMONLY used either as oxidizers or as fuels in explosive or propellant
systems? |
THAT could be answered in a reasonable space.
Examples?
Oxidizer: Trinitroglycerin
Fuel: Nitrocellulose
System: Double based propellants
Oxidizer: Ammonium nitrate
Fuel: Dinitrotoluenes
System: ammonium nitrate explosives
[Edited on 8-2-2018 by Bert]
[Edited on 8-2-2018 by Bert]
Rapopart’s Rules for critical commentary:
1. Attempt to re-express your target’s position so clearly, vividly and fairly that your target says: “Thanks, I wish I’d thought of putting it
that way.”
2. List any points of agreement (especially if they are not matters of general or widespread agreement).
3. Mention anything you have learned from your target.
4. Only then are you permitted to say so much as a word of rebuttal or criticism.
Anatol Rapoport was a Russian-born American mathematical psychologist (1911-2007).
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joseph6355
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| Quote: Originally posted by Bert | | Quote: | | What other EM can I use as fuel or oxygen sources? |
Answered litteraly, that's going to be a very long list. Would this be an acceptable re statement, more or less meeting the intent of your question?
| Quote: | | Which single chemicals, themselves capable of being detonated have been COMMONLY used either as oxidizers or as fuels in explosive or propellant
systems? |
THAT could be answered in a reasonable space.
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Yeah you're right. I should start thinking before writing something.
Not only commonly, but also viable for the home chemist.
I work at mc donalds. 
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