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Author: Subject: Hydrochloric acid / HCL - My formula
Mixell
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[*] posted on 4-3-2011 at 04:54


Well, then sorry for confusing the name of the material my stopper is made of, but the point is its not rubber and it was aggressively attacked in the process of distilling nitric acid (presumably by N2O5).
And about the sarcasm part, I prefer first to explain what is wrong and only if it doesn't help- use sarcasm and stuff...
Anyway, going to sleep for a bit, drinking too much beer in the noon is not a wise thing to do.

[Edited on 4-3-2011 by Mixell]
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hissingnoise
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[*] posted on 4-3-2011 at 05:04


Well OK! But what part of; N<sub>2</sub>O<sub>5</sub> cannot exist in the presence of water, are you having difficulty with?

[edit] Jeeez! I see my post-count has reached 25 . . .

What the fuck am I doing?



[Edited on 4-3-2011 by hissingnoise]
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blogfast25
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[*] posted on 4-3-2011 at 09:07


Quote: Originally posted by hissingnoise  
What the fuck am I doing?


Not sure either, HN… Going by Mixell’s earlier posts I’m still fully expecting him to mix XeF4 with AuCl3 in, I dunno… acetone (whatever)? Just ‘to see what happens!’… He might complain about the stopper being attacked too! Nought queerer than folk...
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Mixell
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[*] posted on 4-3-2011 at 09:12


Oh, never mind, not going to argue about that anymore...
The only thing I'm saying is that N2O5 can exist where there is a phase with a lack of water vapors, just like what happened in my distillation attempt.

That is all.

[Edited on 4-3-2011 by Mixell]
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chem101
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[*] posted on 12-9-2011 at 01:24


Hi, can you please answer my question.

"Hydrogen Chloride, HCl, may be prepared in the laboratory by heating Concentrated Sulphuric Acid, H2SO4, with Sodium Chloride, NaCl."

What happens if we use dilute H2SO4 instead???

:)
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bbartlog
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[*] posted on 12-9-2011 at 05:22


If you use dilute H2SO4, then you end up with HCl in aqueous solution, rather than gaseous HCl being produced. If by 'dilute' you mean 35% or 50% rather than 95%, this would be a reasonable way of getting the aqueous azeotrope on distillation, i.e. you could get 20% (or was it 21%?) HCl this way.
If you use more dilute H2SO4 than that, then you end up with relatively dilute HCl and attempts at distillation would have to drive off some water before you got to the azeotrope.
But the passage you quote is discussing the production of HCl gas, not aqueous solutions, and for that you would want concentrated H2SO4.
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