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Author: Subject: Products of basic Gold(III) Nitrate and hydrogen gas
Dynamic_Equilibrium
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[*] posted on 11-10-2006 at 16:36
Products of basic Gold(III) Nitrate and hydrogen gas


im deeply frustrated by this chemistry problem so ill just cut to it

3H2 + Au(NO3)3 + OH- >>> Au(NO2)3 + 3H2O

that should be right unless it forms nitrogen dioxide gas, dont bases dissociate completely? anyone know the half reactions for this? that'd be great




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[*] posted on 11-10-2006 at 17:38


You're reaction is not balanced as you have a charge of -1 on the left side and 0 on the right side. In addition to having the number of atoms balanced, you also need to balance charge.



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[*] posted on 11-10-2006 at 21:58


It will reduce Au3+ to Au metal.

2Au3+ 3H2 -------> Au + 6H+




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Dynamic_Equilibrium
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[*] posted on 12-10-2006 at 21:38


damn i feel dumb now :mad: , thanks guy, if that is ur real name



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[*] posted on 12-10-2006 at 23:17


Quote:
Originally posted by Dynamic_Equilibrium
damn i feel dumb now :mad: , thanks guy, if that is ur real name


dont worry about it, it happens to all of us. haha




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