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Author: Subject: CS2 + 3Cl2 → CCl4 + S2Cl2
charu_cv3
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[*] posted on 19-9-2006 at 13:33
CS2 + 3Cl2 → CCl4 + S2Cl2


can any one help me by telling me the exact terms & conditions for following reaction to proceed:
CS2 + 3Cl2 → CCl4 + S2Cl2
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12AX7
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[*] posted on 19-9-2006 at 20:23


I would guess whatever makes the Cl2 break into Cl. radicals.

Seems to me CS2 is pretty sensitive already, if I were to guess I'd say it's spontaneous.

But I'm not doing homework for you, you have a textbook and four trillion web pages available to you.

Tim




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[*] posted on 19-9-2006 at 23:33


Quote:
When chlorine is passed into boiling CS2 containing a little iodine, carbon tetrachloride is formed.

CS2 + 3Cl2 => CCl4 (b pt 77) + S2Cl2 (b pt 138)



Partington - A Text Book of Inorganic Chemistry 6th Edition

Check the site's Library section for books that might have more detail.
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matei
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[*] posted on 20-9-2006 at 08:04


Why are you asking?
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