SHADYCHASE54
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Cation exchange media
Hello all,
Let me first say that I am sorry to post this question as a new topic after leaving it in the short questions thread. I don't mean to be a clutter bug
but I am in the middle of somthing and would truly appreciate a responce.
I just have a few quick questions firstly, I have some cation exchange resin in the H+ form and i was wondering if anyone knows how I may determine
the resins exchange potential per/cm3? The resin type is Amberlite IRN-77.
Secondly, would someone out ther is S.M land reccomend a good book that encompasses the theory and thus applications of the various exchange media?
Thurdly and lastly, when I am finished with the media should I regenerate it, dessicate and store or rather leave it spent dissicate and store? I
realize that it is not the job of Sci. M. members to answer my questions and as such please know how truly appreciative I am for any help. thanks in
advance
Shady..
SH
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Melgar
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It depends somewhat on what you're using the resin for. Are you trying to remove something from a solution to get rid of it? Or to collect it later?
What type of ion are you looking to attract?
Here is a nice online FAQ:
http://www.amberlyst.com/faq_general.htm
Here is some good information:
http://www.remco.com/ix.htm
I'm pretty sure you want to keep ion exchange resin wet while it's being stored though. You should've looked up your resin though, the first link I
got in a search told the total exchange capacity.
http://www.dow.com/products/product_detail.page?product=1120...
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Ozone
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In the past, we determined the H2SO4 equivalent (in sulfonated styrene-DVB resins, such as Amberlyst) by:
1. saturating the resin with acid to make sure as many sites as possible are in the H+ form (washing with water to get milky stuff and fines out
(always), then (only with "spent" resins) with dilute sulfuric acid, followed by a water wash).
2. eluting the H+ using NaNO3(aq)
3. titrating the acidity and calculation of the [H+] equivalent to H2SO4.
Cheers,
O3
-Anyone who never made a mistake never tried anything new.
--Albert Einstein
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SHADYCHASE54
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BOO-YHA! Thank you Ozone for the concise responce now I have a place to start from.
SHADYCHASE54.
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