gardul
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math equation question
Good morning,
I think I have been using the wrong equation for a few things. What I need is to figure out how much HLC is in 100ML. but the solution is only 14% HCl
the rest is Water and other impurities.
Below is what I have been using.
Grams of HCl = 14wt% x 100ml / (100 - 14) = 16.27g
is this the correct formula for this? thank you for any help.
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woelen
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No, this is not the correct formula.
You need to look up the density of 14% HCl by weight. This will be larger than 1 gram/ml, albeit not that much larger.
Then multiply the density (call it d) as follows: 0.14 * V * d, where V is the volume in ml and 0.14 is due to the 14% by weight.
Roughly estimating I would say appr. 15 grams per 100 ml, but please do the math more precisely by looking up the density.
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gardul
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Thank you very much. Knew I was messing it up. Your help is much appreciated.
EDIT:
0.14 * 100 * 1.0675 = 14.945g of 14%HCl per 100ml
This seems a little more correct. And would explain why a lot of my results are severly lacking. I want to say thank you again.
[Edited on 21-10-2014 by gardul]
[Edited on 21-10-2014 by gardul]
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kmno4
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A tip:
To calculate density of given percentage (wt), not very diluted HCl aq , it is useful to know that: if your HCl has XY percentage, then its density is
1 + 0,01*0,5*XY.
For example, 10% HCl has density 1,05g/cm3; 20% has 1,10 g/cm3;
18% has 1,09; 30% has 1,15... etc.
It is approximation, but rather good.
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gardul
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Quote: Originally posted by kmno4  | A tip:
To calculate density of given percentage (wt), not very diluted HCl aq , it is useful to know that: if your HCl has XY percentage, then its density is
1 + 0,01*0,5*XY.
For example, 10% HCl has density 1,05g/cm3; 20% has 1,10 g/cm3;
18% has 1,09; 30% has 1,15... etc.
It is approximation, but rather good.
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Thank you for this tip.
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