123chem
Harmless
Posts: 1
Registered: 29-6-2004
Member Is Offline
Mood: No Mood
|
|
theoretical yeild
anyone know how to figure this out:
N2 + 3 H2 = 2 NH3
if 1200 g of N2 is reacted with excess hydrogen, what is the theoretical yeild of NH3
|
|
|
chemoleo
Biochemicus Energeticus
Posts: 3005
Registered: 23-7-2003
Location: England Germany
Member Is Offline
Mood: crystalline
|
|
Now, there is a Beginnings section to ask questions like that.
A simple solution would be (but surely not appreciated by any examiner):
1200g x 17/14 = 1457.1 g of NH3...
Don't ask what I am doing, thats for you to figure 
Never Stop to Begin, and Never Begin to Stop...
Tolerance is good. But not with the intolerant! (Wilhelm Busch)
|
|
|
Proteios
Hazard to Others
Posts: 109
Registered: 7-3-2004
Member Is Offline
Mood: No Mood
|
|
lol.....ive got a better answer than that.....
the theoretical yield is 100 % 
|
|
|
The_Davster
A pnictogen
Posts: 2861
Registered: 18-11-2003
Member Is Offline
Mood: .
|
|
theres also this way.
1200g/28.02 x 2 x 17.04
=1459.5g of NH3
Which is about the same as Chemoleo's way, but mine is more accurate
|
|
|
sanity gone
Harmless
Posts: 38
Registered: 25-4-2004
Member Is Offline
Mood: No Mood
|
|
Lets do the math:
Edit:
Someone else beat me to writing it out, so I drew it out for you.
[Edited on 6/29/2004 by sanity gone]
[Edited on 6/29/2004 by sanity gone]
|
|
|
The_Davster
A pnictogen
Posts: 2861
Registered: 18-11-2003
Member Is Offline
Mood: .
|
|
sanity gone: It was suposed to be 2 mol NH3 over 1 mol N2.
|
|
|
sanity gone
Harmless
Posts: 38
Registered: 25-4-2004
Member Is Offline
Mood: No Mood
|
|
haha, I saw that right after I posted it, damn ADD.
|
|
|
![[*]](images/xpblue/default_icon.gif){kind=icon}
