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Author: Subject: Nucleophilic Substitution
ChemistryGhost
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[*] posted on 10-10-2012 at 14:23
Nucleophilic Substitution


I was thinking would it be possible to do an enolate subtitution(nucleophilic substitution) of ethanamide with 1-Bromo-2,4-dimethoxybenzene. If the following reaction is successful, then a clemmensen reduction will get rid of the ketone. The result would be 2,4-dimethoxyphenethylamine.


pi di 2.jpg - 11kB




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sargent1015
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[*] posted on 10-10-2012 at 16:40


CH3 is not a good leaving group ever... Just sayin



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tetrahedron
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[*] posted on 11-10-2012 at 01:29


Br- is the leaving group..that methyl must be a typo.
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sargent1015
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[*] posted on 11-10-2012 at 04:59


Oh I see it now. You would need a suitable catalyst to remove that Br



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[*] posted on 13-10-2012 at 01:34


Quote: Originally posted by ChemistryGhost  
I was thinking would it be possible to do an enolate subtitution(nucleophilic substitution) of ethanamide with 1-Bromo-2,4-dimethoxybenzene.

The pKa of primary amide N-H is many magnitudes lower than that of its alpha C-H, so it is not possible to obtain an enolate by a monodeprotonation of acetamide.
Otherwise alpha arylations of tertiary amide derived enolates are known. See the literature. Off course, they are not simple nucleophilic substitutions, only formaly so. These reactions proceed by either via photochemical nucleophilic substitution (rarely preparatively useful, unless intramolecular) or via oxidative insertion, ligand exchange and reductive elimination (and thus require a transition metal catalyst). For this later type of arylations, see the chapter Direct Arylation via Cleavage of Activated and Unactivated C-H Bonds (M. Miura, M. Nomura) published in Topics in Current Chemistry 2002, 219 .
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then a clemmensen reduction will get rid of the ketone. The result would be 2,4-dimethoxyphenethylamine.

There is no ketone carbonyl group in the putative product that you depicted. I believe you don't know what a ketone is. Please read about ketones.




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sargent1015
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[*] posted on 13-10-2012 at 09:42


Quote: Originally posted by Nicodem  

The pKa of primary amide N-H is many magnitudes lower than that of its alpha C-H, so it is not possible to obtain an enolate by a monodeprotonation of acetamide.


What if we protected the NH2? Would the single leftover hydrogen still have a lower pKa then the methyl's? I'm trying to think back to my Organic 2 class




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ChemistryGhost
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[*] posted on 26-10-2012 at 17:45
1-chloro-3,4-methylenedioxybenzene to 3,4-methylenedioxy-phenylacetaldehyde


Can 1-chloro-3,4-methylenedioxybenzene react with acetaldehyde in an enolate substitution reaction to form 3,4-methylenedioxy-phenylacetaldehyde. It seems likely. :P
3,4-methylenedioxy-phenylacetaldehyde.


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UnintentionalChaos
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[*] posted on 26-10-2012 at 18:06


Go read up on aromatic reactivity and mechanisms and you'll quickly see that this is impossible.



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