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Author: Subject: pH in IPA
GreenD
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[*] posted on 16-5-2012 at 09:50
pH in IPA


Hello. I've got a problem that I'm not sure how to look at.

I need to create a solution, 20 mL of a certain acid (.2% by weight) in IPA (and H2O if necessary).

The solution must be basic via ammonium hydroxide to a high pH to fully deprotonate all of the acid moieties. Does simply calculating the concentration of NH4OH in IPA give you the pH (i.e. OH- concentration).

How would I go about finding the "pH"?

If you're ambitious;

20mL of a .2% solution of an acid fully deprotonated with (preferably) 25% ammonium hydroxide.

I was fairly poor at calculating pH until one day I had a eureka I understand it, then it disappeared.




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unionised
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[*] posted on 16-5-2012 at 09:55


Measuring pH isn't easy in non-aqueous solutions.

You would probably do better to calculate the number of moles of acid and add a bit more than that number of moles of ammonia.
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GreenD
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[*] posted on 16-5-2012 at 10:10


Quote: Originally posted by unionised  
Measuring pH isn't easy in non-aqueous solutions.

You would probably do better to calculate the number of moles of acid and add a bit more than that number of moles of ammonia.


Ok, yeah because it isn't actually pH anymore, right?

But still, if you had an excess of base, you would have a fully deprotonated acid in IPA, right? There aren't some weird occurences where the equivalents of base needs to be really high or something?

Since carboxylic acids can be easily deprotonated by ammonium hydroxide a ~1.2:1 base:acid should fully deprotonate, right?




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