jonco
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Making tin sulphate
Hi,
Does anyone know of a quick and easy way to make tin sulphate?
Thanks
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IrC
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Sn (s) + CuSO4 (aq) → Cu (s) + SnSO4 (aq)
Let me guess. Google is blocked on your computer right?
"Science is the belief in the ignorance of the experts" Richard Feynman
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jonco
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I tried Google but most of the hits I got was advertising from companies trying to sell me stuff 
The internet has been taken over by them.
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jonco
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Do you have more information on using CuSo4 i.e. how many grams CuSO4 to ml water, how grams of tin to add, what is the yield efficiency, how many
grams tin sulphate will I get etc?
Thanks
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IrC
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Solubility in water, pentahydrate 316 g/L (0 °C) 2033 g/L (100 °C)
Cu atomic number 29
Sn atomic number 50
Go figure.
"Science is the belief in the ignorance of the experts" Richard Feynman
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Bot0nist
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<a href="http://cavemanchemistry.com/oldcave/projects/stoich/index.html">Use Stoichiometry, Duh!</a> 
You would do yourself a great service by taking the time to learn the math behind chemistry. I know it's boring, but once you know it's like riding a
bike, you know?
[Edited on 22-5-2011 by Bot0nist]
U.T.F.S.E. and learn the joys of autodidacticism!
Don't judge each day only by the harvest you reap, but also by the seeds you sow.
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cyanureeves
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Bot0nist thank you for that caveman site.
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jonco
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I still don't know how to calculate it
I added 10g of CuSO4 to 100ml of water. I then added some pieces of tin approx 5g. Nothing happens except the tin turns dark in the blue solution.
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IrC
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Not trying to be rude but if you are not willing to at least try no one will like helping you. At 316gm/L you needed 31.6 gm to saturate .1L or 100
ml. Plus you do not provide information yet want answers. At what temperature? If you had said "I tried heating it" or "I added more salt to get to
the 31.6 gm needed" at least one would think you are worth helping. Going to such a simple yet well written explanation as Caveman you are not doing
yourself favors by not trying real hard to understand it instead of saying "I can't figure it out".
I do however give you credit for at least trying the reaction. Many reactions need a predominance of something to head in the right direction. In your
case more salt, more heat, less questions.
I am not even good at chemistry, nothing compared to someone like Woelen but I can see at least this much. My mad science predominates in things high
voltage, high vacuum, radioactive, and very very mad. Or at least dangerous but not stupid - rather I spend most my time in research before I do
anything. Otherwise why bother.
I should add: did you just try simply putting tin in sulfuric acid? Drain an old battery if need be it's a start. I think.
[Edited on 5-22-2011 by IrC]
"Science is the belief in the ignorance of the experts" Richard Feynman
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The WiZard is In
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Sure. Commercial production is from Tin oxide (SnO) and H2SO4.
Hummmm... Sn and H2SO4...a problem often with chemistry
— the obvious doesn't work — easily if at all. Brauer Handbook
of Preparative Inorganic Chemistry. The book is in
the forum's library. Starts prep of Sn(SO4)2 by boiling
tin metal in conc. H2SO4 producing alpha-stannic acid, from
which tin (IV) sulphate dobe made using.... H2SO4...!
DL la book. I will at no extra charge save you some trouble — you
be wanting pages — 737 & 744. I would go with the SnO method.
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The WiZard is In
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Good old Mellor VII:328-9 describes several other synthesis,
however, they are chemically messy e.g., you also get —
SO2 - NO2 - H2S - sulphur sesquioxide (from Sn and pyrosulphuric acid).
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jonco
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Can someone check this and let me know if it is correct?
Let's say I want to make 10g/100ml of tin(II) sulphate, with almost no Tin(IV) sulphate. I will use the reaction between Sn and CuSO4.5H2O:
Sn + CuSO4 -> Cu + SnSO4
Molar mass of:
Tin : 118.71g/mol
CuSO4: 159.62g/mol
CuSO4.5H2O: 249.70g/mol
Stoichiometrically, the number of grams of CuSO4 needed to completely react with the tin is:
(10/118.71)(159.62) = 13.45g
I will need (13.45)(249.70/159.62) = 21.04g of CuSO4.5H2O, which I will dissolve in 100ml of water.
To this, I will add tin > 10g, to ensure all CuSO4 used in the reaction.
One question remains. How do I know when the reaction is complete?
Thanks to WiZard for recommending those two books.
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MrHomeScientist
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You'll know the reaction is complete when the solution goes colorless. Cu 2+ ions are blue in solution, so once those have been used up in the
reaction the color will disappear.
Did you mean you want to produce 10g of SnSO4, or use 10g of Sn metal for the reaction? Your calculations are for the latter situation (and they are
correct, if that's what you meant to calculate).
[Edited on 5-23-2011 by MrHomeScientist]
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jonco
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I wanted to produce 10g/100ml of Tin(II) sulphate (SnSO4) solution. I calculated how much CuSO4 is required so that when all the CuSO4 is used up,
I'll have 10g/100ml of
tin(II) sulphate in solution. I added excess tin to ensure all CuSO4 is used up.
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cyanureeves
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there is a guy on youtube that makes tin sulfate by using tin as anode and cathode in sulfuric acid solution. but that displacing stuff is really
cooler,i didnt know you could swap copper with tin, zinc with silver chloride and lead with copper in copper acetate solution until i read it here.
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MrHomeScientist
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Jonco, if you want 10g of tin sulfate product then I believe you'll only need 11.6g CuSO4.5H2O and 5.5g of tin.
Since we want 10g SnSO4, we start there and calculate how much CuSO4 is needed:
10g * (1mol/215g) * (249.5g/1mol) = 11.6g CuSO4.5H2O
Starting from the same point, calculate how much tin is needed:
10g * (1mol/215g) * (119g/1mol) = 5.5g Sn
So you can still use 10g tin as a large excess but you only need 11.6g copper sulfate to make your solution, if my math is correct.
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digitalemu
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It really is quite simple if you don't care much about the formed copper powder. You do not need to saturate the solution with CuSo4. Just mix up
some CuSo4 with water, throw in an excess of tin, heat it up a bit close to boiling, wait until blue color goes away(if it doesn't then throw in some
more tin). Filter and then boil down and let crystallize overnight. Who needs a beaker when you have a bucket. 
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Mixell
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I'll just post my two cents here:
Preferably use tin foil or powder, and not tin ingot. Because it may form a passivated layer of copper and the reaction would stop to a halt (it
happened to me with indium, I assume a tin ingot would exhibit the same property).
If you got ingots and you don't want to mess with melting or thinning them down, then the electrolysis in sulfuric acid method is preferable.
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plante1999
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i agree with mixell, you will prefably smash the ingot/shot with an hammer that is wraped with poly bag.
I never asked for this.
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LanthanumK
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I have done this reaction already. The tin turns black, but continues to slowly dissolve, forming a white precipitate (tin oxysulfate?), which was
probably the result of my rather basic copper sulfate solution. Wait about a week.
Smashing a tin ingot with a hammer is likely to squash it into a thick foil. Tin is a very soft metal.
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ampakine
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Does H2SO4 not oxidise tin?
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Mixell
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It should, but probably only effective at high temperatures.
Also, according to Wikipedia's standard electrode potential, it should even oxidize tin to Sn(IV).
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