Is it possible to make mercury(I) fulminate the same way as mercury(II) fulminate?
Not sure, but from what I have learned of Hg(ll) is that with Hg, one gets Hg(l). To quote a source (http://mercury.atomistry.com/chemical_properties.html ):
"whilst mercuric salts, with excess of mercury, form mercurous salts."
which is a property demonstrated by copper salts also.
|