I have reviewed some of the literature and the first observation is that the alluded to iron oxide for the industrial processing of H2S is Fe3O4
(reference, see "Sulphide Scavengers in Oil and Gas Industry – A Review" by M.K. Amosa, I.A. Mohammed, and S.A. Yaroor), more meaningfully, as this
is a mixed valence salt, FeO.Fe2O3. Cited summary reaction (of which I chemically disagree owing to the absence of dissolved or gaseous oxygen, but
the reaction may approximate observed performance of the iron oxide on hydrogen sulfide removal):
" Fe3O4 + 6 H2S → 3 FeS2 + 4 H2O + 2 H2 (10)"
The success of this salt suggests to me a cyclic process between valence states of iron. Further research led to this work: "Free Radicals and
Chemiluminescence as Products of the Spontaneous Oxidation of Sulfide in Seawater, and Their Biological Implications", by DAVID W. TAPLEY,GARRY R.
BUETTNER, and J. MALCOLM SHICK, in Biol Bull. 1999 Feb 1; 196(1): 52–56. available at https://www.ncbi.nlm.nih.gov/pmc/articles/PMC4295652/ .
Read this work, in particular reactions (2) to (10) to understand the likely underlying mechanics cited below:
HS• + O2 → HO2• + S (2)
or: HS• + O2 → HSO2• (7)
followed by: HSO2• → H+ + SO2•- (9)
SO2•- + O2 → SO2 + O2•- (10)
HS• + O2•- → S + HO2- (3)
At near-neutral pH, HO2− will immediately protonate:
HO2- + H+ → H2O2 (4)
The proposed metal-catalyzed mechanism for metal M at valence state 'n+' via metal auto-oxidation of oxygen creating the superoxide radical anion:
M(n+) + O2 → M(n+1)+ + O2•- (5)
This oxidation is complemented by the reducing HS- ion:
M(n+1)+ + HS- → M(n+) + HS• (6)
The formation of H2O2 can lead to hydroxyl radical and with H2S more HS•
Fe(ll) + H2O2 + H+ --> Fe(lll) + OH• + H2O
OH• + H2S --> H2O + HS•
In my opinion, the recycling of the valence states of Fe3O4 is the key to its success.
[Edited on 23-3-2018 by AJKOER] |