I told you! It looks like you've ignored my link, while it was the correct answer - you've got iodine monochloride via I2 + Cl2 -> ICl. Iodine
monochloride is somewhat soluble in water, while better also soluble in ethyl acetate. In water iodine mnochloride disproportianates ICl + H2O ->
HCl + HOI. That's why bicarbonate is needed - to neutralize HCl (bicarbonate does not form hypochlorite-hypoiodite, only carbonate does). However, I'm
not sure whether this reaction is correct or if there's some tricks in measuring reagent amounts..
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