EnvSciMOOSE - 11-9-2005 at 17:11
Quick question on the setup of this problem, where do i start with these numbers??:
Calculate the catechol (substrate) concentration of a solution prepared by mixing:
18 drops 0.01M catechol + 2 drops water (assume 20 drops = 1mL)
8mL Deionized water
1.0 mL aqueous enzyme extract
thank you!!
Magpie - 11-9-2005 at 20:04
Assuming you want it as a molarity:
M1V1 = M2V2
M2 = (M1V1)/V2 = [(0.01)(18/20)]/(18/20 +2/20 +8 +1)
BTW this is not stoichiometry but a concentration calculation.