What is the best way to analyse the concentration of NaClO in a mixed NaCl + NaClO aqueous solution, formed from electrolysis?
By best I mean quick, convenient and accurate within 1%.
I thought about adding dilute hydrogen peroxide and measuring the volume of O2, but H2O2 is not easy to get these days.
What about heating the solution strongly? At what temperature does NaClO decompose, and will it decompose only as follows:
2NaClO -> 2 NaCl + O2
The gas that comes off will be a mixture of water vapor and oxygen. Can I separate the two by just bubbling the gas through a water trap?
Thanks.gdflp - 4-11-2014 at 18:28
No it will mainly decompose as follows, 3NaClO --> 2NaCl + NaClO3. Adding some HCl and measuring the amount of chlorine gas which results may be
suitable.Edison - 4-11-2014 at 18:57
Thanks. I thought about that, but Cl2 is fairly soluble in water at RTP.
Should I keep the water hot, at say 90 Celcius, to reduce Cl2's solubility?
Would the reaction between NaClO and HCl be as follows:
NaClO + HCl -> NaOH + Cl2
Effectively the addition of HCl reverses the reaction between the Cl2 formed at the anode and the NaOH formed at the cathode, which combined to form
NaClO + NaCl?
So I can deduce that one mole of Cl2 gas would be formed from one mole of NaClO?blogfast25 - 5-11-2014 at 06:01
