No, no. You DO account the 5. CAN is a double salt of 5 mol Ca(NO3)2, 1 mol NH4NO3 and 10 mol hydrate water.
So the molar mass of CAN is 5 times the molar mass of calcium nitrate plus the molar mass of ammonium nitrate plus 10 times the molar mass of water.
That gives me a 1080 g/mol.
Per mol of CAN, you'll need 11 mol of NaOH (stoichiometrically) to covert all Ca to Ca(OH)2 and all ammonium to ammonia. So 11 mol x 40 g/mol = 440 g
NaOH.
A kg of CAN would roughly yield 24 L (STP) of NH3.
http://en.wikipedia.org/wiki/Calcium_ammonium_nitrate
Now be a good lad and start with 100 g of CAN, to see if you can do it. ![;)](./images/smilies/wink.gif)
[Edited on 23-10-2014 by blogfast25] |