25heat - 19-2-2014 at 12:42
1) The atomic orbitals of metals overlap in the solid to form molecular orbitals that explain why metals are such good conductors of electricity. If
we consider only the valence shell S and P orbitals of strontium, how many orbitals will be formed from 5,000 strontium atoms?
How many of these would be filled?
Rate of Consumption and Appearance
25heat - 19-2-2014 at 12:46
Please help with this problem.
Given the hypothetical reaction where A and B react to form C and D, if the rate of consumption of A is 0.086 M/min what is the rate of appearance of
C and D?
2 A + 2 B → 4 C + 3 D
Rate of Consumption of B=
Rate of Appearance of C=
Rate of Appearance of D=
bfesser - 19-2-2014 at 13:28
You haven't asked for help; you've asked for answers. We're not here to answer your homework problems. Make an attempt before asking again.
Help with Atomic Orbitals
25heat - 19-2-2014 at 13:36
ok im reposting it because apparently I have to show my work. Obviously I attempted the problem.
Given the hypothetical reaction where A and B react to form C and D, if the rate of consumption of A is 0.086 M/min what is the rate of appearance of
C and D?
2 A + 2 B → 4 C + 3 D
Rate of Consumption of B=
Rate of Appearance of C=
Rate of Appearance of D=
What I did was use the molar ratios using the given A. but shouldnt A be negative in the first place since it is on the left side? Or is it vice
versa?
.086(2/2)=.086
.086(4/2)=.172
.086(3/2)= .129
Help with rate of consumption WITH WORK
25heat - 19-2-2014 at 13:39
Given the hypothetical reaction where A and B react to form C and D, if the rate of consumption of A is 0.086 M/min what is the rate of appearance of
C and D?
2 A + 2 B → 4 C + 3 D
Rate of Consumption of B=
Rate of Appearance of C=
Rate of Appearance of D=
What I did was use the molar ratios using the given A. but shouldnt A be negative in the first place since it is on the left side? Or is it vice
versa?
.086(2/2)=.086
.086(4/2)=.172
.086(3/2)= .129
[Edited on 19-2-2014 by 25heat]
bfesser - 19-2-2014 at 13:41
Don't forget to include units in your answers!
[edit] Stop re-posting this in Chemistry in General; it belongs in Beginnings.
[Edited on 19.2.14 by bfesser]
Galinstan - 19-2-2014 at 13:43
why is this called help with atomic orbital when it obviously has nothing to do with them, and you are correct in your calculations and A shoulnd't be
negative because it is rate of consumption not rate of apearence.