whatsonot - 10-12-2013 at 23:54
Is it possible to do the above similar to this synthesis of 2C-B? http://about.mdma.ch/000393925.html
Just take some 2C-H.HCl throw in some 70% HNO3 in GAA?
EDIT: Oops meant pea not benzaldehyde
[Edited on 11-12-2013 by whatsonot]
[Edited on 11-12-2013 by whatsonot]
turd - 11-12-2013 at 02:22
I think you are confused - benzaldehyde is not basic and therefore there is no benzaldehyde.HCl
Is your question whether you can directly nitrate 2C-H.HCl without going via the freebase? I'm quite sure you can, since you would form the nitrate
anyway. Unless the hydrochloride is much less soluble than the nitrate.
But why would you!? 2C-N is neither very potent nor interesting. I hope you're at least talking about the amphetamine analogue...
Edit: typo
[Edited on 11-12-2013 by turd]
whatsonot - 11-12-2013 at 07:50
Yea I meant phenethylamine not benzaldehyde.
Just a curiosity.
EDIT: Any idea how to precipitate the 2C-N out the GAA? I tried the reaction with the same stochiometry as in PiHKAL but less GAA (6 mL for 1.1 g
2C-H.HCl) and no 2C-N precipitated out.
[Edited on 12-12-2013 by whatsonot]