Quote: Originally posted by papaya | How you managed to calculate double power woelen ? Diode strips the "half" of the wave, so ideally power is halved, even if peak voltage remains
high. [...] | If you double the voltage, while keeping the load the same, then you take 4 times more power.
You cut away half of the wave form, so what remains is 0.5*4 times the original power, hence double the power of a full 110 V AC wave.
Power is proportional to the square of applied voltage!
[Edited on 27-8-13 by woelen] |