@Ax165Xj:
A good starting point is stoichiometry. For instance, oxidation of a primary alcohol to carboxylic acid:
R-CH2-OH + H2O === > R - COOH + 4 H+ + 4 e- ... Eq.1
Reduction of the Cr2O7(2-):
Cr2O7(2-) + 14 H+ + 6 e- ==== > 2 Cr3+ + 7 H2O ... Eq.2
Then 6 x Eq.1 + 4 x Eq.2, eliminate any redundant H+ and H2O on either side of the equation, and add SO4(2-) to the left to convert H+ to H2SO4 and K+
to obtain K2Cr2O7.
This gives you the theoretical minimal amount of potassium dichromate and sulphuric acid per mole of primary alcohol. A stoichiometric amount of
K2Cr2O7 probably works but you'll need some excess acid.
If you're dealing with a water soluble substrate you should have no problems but two phase reactions could be a lot trickier.
[Edited on 1-7-2013 by blogfast25] |