The ammonium nitrate method will certainly work. But it's a boiling down and scraping for yield-type reaction, which are never fun.
1.89g Ca(OH)2 in 1000mL of water to be more precise (if at 0 C). Which would give 4.18g of Ca(NO3)2 in theory.
To put things in perspective, if you want 100g Ca(NO3)2, you need 45.24g Ca(OH)2 in about 24,000 mL of H2O!
Note: Solubility data of Ca(OH)2: 4.447 g/L aq. NH4Cl solvates 4.42g/L Ca(OH)2 at 25 C (source). So if it is similar for NH4NO3, then you would need less water (2.33 times less water if it's the same, but it's still a ton of H2O).
[Edited on 28-2-2013 by Formatik] |