bluevelvet12 - 9-11-2012 at 04:30
I've been trying to work out how much CaO and/or CaCO3 is needed to bring sea water from pH 8.1 to 8.3, and then again at pH 7.9 to 8.3. I've gone
through the acid-base reactions and tried to work it out, but am quite confused as it is not as simple as I expected it was.
If six major ions make up >99% of the total dissolved in seawater [sodium ion (Na+), chloride (Cl-), sulfate (SO42-), magnesium ion (Mg2+), calcium
ion (Ca2+), and potassium ion (K+)], I wasn't sure how this would effect working out the equation, and how different would the result come out than if
simplifying it by using regular H2O set at pH 7.9 and 8.1 to bring both up to pH 8.3? How would the 3.5% salinity effect the amount of CaO or CaCO3
you needed to add?
blogfast25 - 9-11-2012 at 06:47
It's not at all easy to work out theoretically, for one because sea water also contains CO2 which with carbonates forms bicarbonates.
Urzah - 9-11-2012 at 08:04
If you want to use natural seawater, you cant do it theorically. Youll need to test it in a methodic way. Seawater, as any natural product, dont have
équal amounts of ions in it from day to day.
You'll have to test it directly.