Reverend Necroticus Rex - 15-6-2004 at 10:57
I just tried to make sodamide, stupidly forgetting that it reacts in a vicious fashion with water, I tried mixing NH3 with NaOH, ofcourse it got quite
violent, It released lots of NH3, but what would be the other decomposition product? neither me or my friend are totally sure,
I'm thinking, it forms sodamide in-situ, which decomposes to give sodium azide and NH3, which MAYBE decomposes in solution to hydrazoic acid. Is
this right? I'm confused.
Geomancer - 15-6-2004 at 11:13
This is in water solution, right? Adding base simply lowers the solubility of ammonia, by eating up the protons needed to form the ammonium cation.
Reverend Necroticus Rex - 15-6-2004 at 11:16
Thanks geomancer, so basically, I'm left with a very dilute solution of NH3 , and NaOH? 
I say this, becaused I'm confused, whan I did it, the solution went very milky, although this could be because I used an empty H2O2 bottle to do
the reaction in, what would be the products of H2O2 in the mix?
[Edited on 15-6-2004 by Reverend Necroticus Rex]
The_Davster - 15-6-2004 at 14:37
When sodamide reacts with water, NaOH and ammonia are formed. The milkyness could have been caused by sodamide in the water before it reacted or
possibly by lots of ammonia microbubbles making it appear milky.
[Edited on 15-6-2004 by rogue chemist]
Reverend Necroticus Rex - 15-6-2004 at 15:04
Hmmm, yeah it could be, but on the other hand, that wouldnt explain why it does it only when H2O2 is present, I mixed them again to try and see if the
milky color occurs without the presence of peroxide, and it only happens when peroxide is added. I can't figure out what the reaction would be.