So, if I have about 3g of 14K gold (copper/gold) dissolved in HCl/H2O2, can I simply place a small rod of copper in to precipitate out the gold as per
reactivity series?
[Edited on 21-8-2012 by liquidlightning]kristofvagyok - 21-8-2012 at 13:40
I don't like that method. It works, but it won't be extra pure...
Pass through some SO2 (gas), it will drop out the gold from the solution, nothing else.Diablo - 21-8-2012 at 23:08
The gold usually separates out in a finely divided state, and appears brown by reflected light and greenish blue by transmitted light. If very dilte
solutions are used, the gold sometimes separates out forming a yellowish film on the sides of the test tube.
Another site (link: http://www.finishing.com/345/32.shtml ) notes that the yield using SO2 is only around 75% and to increase the recommendation is, to quote: "To
drop a larger % you must slowly heat solution to simmering, just below 200 f (do not boil). Wait at least 1 hour before filtering, re-filter."
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Another point is that the Gold was dissolved with HCl/H2O2, which is equivalent to using Chlorine water (effectively HOCl/HCl). Now, per US Patent
4,662,938 ( link: http://www.google.com/patents/US4662938 ): "The solid residue containing the gold is then leached with hypochlorous acid to dissolve the gold, and
after separating the solids form the gold-containing hypochlorous acid leach solution, the gold is precipitated by contacting the solution with sulfur
dioxide."