Sciencemadness Discussion Board

hi H2N-(CH2)5-COOK

cazruto - 29-6-2012 at 18:50

H2N-(CH2)5-COOH + KOH = H2N-(CH2)5-COOK hi is it possible ?

Hexavalent - 30-6-2012 at 02:02

Possibly, I suspect that with correct stoichiometry a simple acid/base neutralization would take place to produce the salt you mention and water.

For reference - H2N-(CH2)5-COOH is 6-aminoacetic acid

and

H2N-(CH2)5-COOK is potassium 6-aminoacetate.



EDITED to correct the IUPAC name for the 'H2N-(CH2)5-COOH'.

[Edited on 30-6-2012 by Hexavalent]

kavu - 30-6-2012 at 03:38

Quote: Originally posted by Hexavalent  

For reference - H2N-(CH2)5-COOH is 2-aminoacetic acid


Did you catch the 5 in methylenes. It's aminocaproic acid or in IUPAC 6-aminohexanoic acid. As for the reaction, it does proceed as you suspected. KOH is strong enough base to overcome the buffering effect of the zwitterion.