Interesting. I'd heard that using: K2SO4 + Na2CO3 --> K2CO3 + Na2SO4 works. I think the key here is that Na2SO4 becomes less soluble then K2SO4 at
around 0 degrees C, and so with careful cooling down to around that temperature, all or most of the Na2SO4 can be removed by filtration, leaving
behind a K2CO3 solution, which is very dilute.
The problem with that process though, is that it would be very tedious to carry out, since you are dealing with very dilute solutions (solubility of
Na2SO4 is only 47.6 g/L @ 0 deg. C) in order to isolate just a little K2CO4. A large initial amount of water would be needed just to get the reactants
dissolved. I just don't see how this would be more effecient then what I had proposed.
By using a similar process, substituting KCl for K2SO4, and utilizing heat and evaporation to acheive a fractional crystallization of NaCl (instead of
freezing/cooling), better yields of K2CO3 may be had, owing to the fact that the concentration of salts in a water solution will generally be greater
at warm/hot temperatures. Also, the degree of difference between the solubilities of Na2CO3, K2CO3, NaCl, and KCl seem more favorable for separation,
in comparison to the first scheme which utilizes K2SO4.
*
I also wanted to add that, although it might be difficult to test for sodium impurities in the final K2CO3 product, maybe by first neutralizing the
K2CO3 solution with acetic acid, and then precipitating any residual Cl- ions that might be present, by adding lead acetate solution until no more
precipitate forms, filtering and weighing it, could give at best a rough determination of how effective the selective fractional crystallization is,
in getting mainly the NaCl out of the solution.
[Edited on 20-3-2012 by chemicalmixer] |