Stomper - 21-11-2011 at 17:11
Hi Guys,
I’m new to the whole world of chemistry since my new job requires me to have an understanding of propellants.
I have been given a few assignments to help me learn, and to date I have managed to get through them
However my latest assignment started to talk about calculating the Oxygen Balances [OB] for Double Based Propellants (DBP).
In particular the following question:
Find the OB[%] of a DBP made from Nitrocellulose (C6H7O2) (OH) (ONO2)2 and Nitro-Glycerine ( C3H5N3O9) with a weight ratio of 50% each.
I am able to solve it as shown below.. But I have no idea if I am on the right path or I have made a mistake.. Any help that anyone can give will be
great!!
NC – Oxygen deficiency of -7, and NG- Oxygen excess of 0.5
NC = (50/252) x -7 = -1.3889
NG = (50/227) x 0.5 = 0.110132
Therefore net for DBP = (-1.3889+0.110132) = -1.27875
Where MW of the DBP is (227+252)/2 = 239.5
OB[%] = (-1.27875 x1600)/239.5 = -8.542%