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Based on this related work with free bromine formation (and not complexed), see 'Hydroperoxyl radical (HO2•) oxidizes dibromide radical anion
(•Br2−) to bromine (Br2) in aqueous solution: Implications for the formation of Br2 in the marine boundary layer', see the work by Brendan M.
Matthew, et al, fully available (for free) at: https://agupubs.onlinelibrary.wiley.com/doi/full/10.1029/200... , one probably needs something like HO2• to remove the likely persistent I2•-
radical.
Assuming the iodine chemistry is in line bromine chemistry (see https://pubs.acs.org/doi/10.1021/j100398a045), we want hydroxyl radicals (OH•) and therefrom perhydroxyl radical (HO2• ) in acidic conditions,
producing the following reaction system interacting with bromide (or, in the current case, iodide) and H2O2 per the cited reference reaction system:
Br- + OH• --> BrOH•-
BrOH•- --> Br- + OH• (the reversible reaction of above)
BrOH•- + H+ --> Br• + H2O
OH• + H2O2 --> H2O + HO2•
Br• + Br• --> Br2
Br• + Br- --> Br2•-
Br2•- + Br2•- --> 2 Br- + Br2
Br2•- + HO2• --> Br2 + HO2-
And apparently concurrently with the above:
Br2•- + HO2• --> 2 Br- + O2 + H+
H+ + HO2- = H2O2
Now, as to best path to HO2•, based on my recent experiments, I recommend the action of the microwave (MV) on carbon (as graphite rods, and not
activated charcoal which absorbs iodine), which may form surface zones containing a deficiency and excess of electrons:
C(surface) + MV → C(+) + e-
which together with an acid source of H+ and H2O2, may produce a one electron reduction of the hydrogen peroxide, as follows:
In the cathodic Zone:
H2O2 ⇌ H+ + HO2-
e- + H+ = H•
followed by an attack on the H2O2 leading to radical formations (see http://www.ipb.pt/~htgomes/FCT110088-%5B2%5D.pdf equations (3) and (4), in particular).
My take is as follows:
H• + HO2- = OH- + OH•
OH• + H2O2 ---> HO2• + H2O (see https://pubs.acs.org/doi/abs/10.1021/jp100204z )
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[Edited on 24-6-2019 by AJKOER] |