So in 300 ml of this liter solution there will be 300/1000 * 0.1 = 0.03 moles of Pb(NO3)2.
To this is now added 1.3/65.4 = 0.02 moles of Zn.
This will undergo a reaction, Pb(NO3)2 + Zn -> Zn(NO3)2 + Pb, as suggested by the answers the question requires.
Since zinc and lead have the same valence here, 0.02 moles of zinc simply trade places with 0.02 moles of lead,
which leave 0.01 moles of Pb(NO3)2 in solution, and 0.02 moles of lead as precipitate. The atomic weight of lead is 207, so this will be 4.14 grams of
lead.
The remaining 700ml of solution (which I think is not likely to be the subject of the question) of course has 0.07 moles of Pb(NO3)2 left in it.
I don't know what 'championship' this is for but this is not a very difficult question.
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