Runningbear - 9-3-2010 at 03:15
Hi Guys,
I want to make a small amount of KOH from potassium carbonate and calcium hydroxide. Can anyone tell me the correct percentage of each I should be
boiling?
Thanks in advance,
Runningbear
Jor - 9-3-2010 at 03:28
1 mole of potassium carbonate per 1 mole of calcium hydroxide. Take a slight excess of potassium carbonate because it is hygroscopic (so contains some
water) and you will have carbonate in your hydroxide anways (by reaction with CO2 from the air) and calcium interferes in much more reactions than
carbonate.
Runningbear - 11-3-2010 at 04:33
Thanks for the feedback Jor.
Potassium bicarbonate is 100.12 grams per mole
Calcium hydroxide 74.093 grams per mole
Allowing for the hydroscopic nature of potassium carbonate, I'm guessing about a 10% excess should be used.
So the correct ratios would be approximately 110 grams potassium carbonate to 75 gram calcium hydroxide?
Does that sound about right?