Another possible approach would be to convert the SnO2 to sodium stannate, Na2SnO3, via fusion with Na2CO3. Then convert this to alpha-metastannic
acid, H2SnO3, using HCl. Further treatment with con HCl should yield SnCl6--. Reacting this with aluminum wire should reduce it to SnCl4--. In this
form it can be qualitatively tested with HgCl2 and verified as tin. Does this sound reasonable?
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