@Murexide: I ground up 4 tablets with a mortar and pestle and then weighed (massed!) ~0.3 g samples, which I calculated should require more than 10 ml
of titrant, to give me 4 SF for the volumes; but looking back at my laboratory manual notes, I don't know what I was thinking because the balance I
was using at that time only measured to 0.01 g, so the 2 SF of the sample weight was the limiting factor in the calculations.
@hacker: the only indicator that you will need is phenolphthalein. What do you plan to do with the phenol? (Just curious.)
Just a thought about my philosophy of using the purest chemicals that you can get or prepare youself. Let's assume 3 step synthesis: A -> B -> C
_> D, where A is the starting material B & C are intermediates that are prepared and isolated, and D is the product.
a) assume A, B, C, and D are all isolated and are 100% pure, but the yield is just 0.9 (()%). The overall yield is then 0.9 x 0.9 x 0.9 = 0.7 or 70%.
b) now assume the same conditions but the yield in each step is 70%; the overall yield will be just 50%.
Now assume that the yields are the same in each scenario, and the purities of A, B, C, and D are 90% and 70 % respectively. In the first case you get
a 90% yield of 70% pure product; in the second case you get a 50% yield of 50% pure product.
I think this is an over-simplified example, but I think the point is that one would prefer to get as high a yield of as pure a product as possible,
both for reasons of efficiency and economy. Do I make sense or am I just whistling in the wind? (In my defense, it has been 40 years since I practiced
chemistry professionally, and in getting back to some amateur chemistry in the last year I am very distressed at how much chemistry I have forgotten,
let alone how much new chemistry has been discovered since then.)
P.S. I welcome constructive criticism, but please don't be too hard on an old man!
[Edited on 12-31-2018 by CharlieA] |