Originally posted by Nicodem
Quote: | Originally posted by BobHawson
Found this on the same site, do you folks think substituting 5-hydroxytryptophan for 3,5-dimethoxy-4-hydroxy-benzaldehyde in this route would yield
5-methoxytryptophan? |
What about learning some basic chemistry before hurting or poisoning yourself?
Sodium methoxide is not a methylating reagent. It is a base and nucleophile. For example, in the example you mention, it is used in an
S<sub>RN</sub>1 aromatic nucleophilic substitution which however is completely unrelated to O-methylation of 5-hydroxytryptophan
which is not really feasible without N-protection (the carboxylic group does not really need protection as the formed methyl ester is easily
cleaved, for example concurrently with N-deprotection).
PS: Please post beginners question in the Beginners section where I'm moving this thread. Else, if you prefer to post them in the Organic section just
add a few references to your thread opening post so that it will at least appear like you actually did some literature search before posting.
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