I said above that for my next experiments that I would save the methanol and go with water. This is apparently a bad idea if the reducer is sodium
sulfide and the sodium bicarbonate buffer is used. From Hodgson and Ward, "while the addition of sodium bicarbonate to the sodium sulphide in alcohol
greatly improved the reduction efficiency, this does not occur in water alone (see Table II, Experiment 6) since the water-soluble sodium carbonate
formed (insoluble in the methanol medium) probably introduces the alkalinity necessary for by-product formation with 20% diminution in yield of
picramic acid." Makes sense now that I stop and think about it.
I might try the following in water though. The idea, which came from the Zinin article, is to use a magnesium salt that would precipitate the
hydroxide formed from the reduction reaction, as magnesium hydroxide, thereby keeping the pH of the reaction solution from rising and preventing
undesirable by-product formation. Epsom salt is magnesium sulfate heptahydrate and would probably work fine.
MgSO4 (aq) + 2NaOH (aq) -------> Mg(OH)2 (s) + Na2SO4 (aq)
If it wasn't possible to separate the magnesium hydroxide and sodium picramate from each other after the reaction was complete, the sodium picramate
could be precipitated as usually and then dissolved in water before filtering out the magnesium hydroxide. Acidifying the sodium picramate solution
would then precipitate picramic acid. I think my next experiment may involve Epsom salt.
I am not sure how difficult it will be to remove the precipitated magnesium hydroxide from the sodium picramate solution. It seems like it may be
difficult to filter. As long as it can be removed with a reasonable amount of effort, this process would likely be a good way of reducing bi-product
formation and increasing yields.
[Edited on 9-4-2014 by Hennig Brand] |