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Author: Subject: Formation of copper(I) ammine complex
LanthanumK
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[*] posted on 11-6-2011 at 05:58
Formation of copper(I) ammine complex


When copper dissolves in an aqueous solution of ammonia containing some dissolved oxygen, does the copper(I) ammine complex or the copper(II) ammine complex form?



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#maverick#
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[*] posted on 11-6-2011 at 08:37


Copper (II) tetramine complex I believe if u add NH3 to any copper (II) solution



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[*] posted on 11-6-2011 at 12:59


Elemental copper isn't appreciably attacked by ammonia solutions. But both Cu<sup>2+</sup> and Cu<sup>+</sup> ions form diammonia complexes. Water insoluble white CuCl dissolves in ammonia solutions...
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LanthanumK
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[*] posted on 11-6-2011 at 15:11


I am trying to use ammonia to prove whether a red precipitate is Cu2O or Cu; if that helps.



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AJKOER
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[*] posted on 11-6-2011 at 16:05


You could try dissolving in HClO.

If Copper, then Copper Oxygen Chloride is formed (a double salt). Formula CuCl2.Cu(OH)2

If CuO, the same double salt plus oxygen bubbles.
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LanthanumK
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[*] posted on 11-6-2011 at 18:01


Cu2O, not CuO. Which one did you mean?



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AJKOER
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[*] posted on 12-6-2011 at 12:27


OK,

2 HClO + 2 Cu --> CuCl2.Cu(OH)2

which is Copper (II) Oxygen Chloride, which forms green crystalline needles.

Or,

4 HClO + 2 Cu2O --> 2 CuCl2.Cu(OH)2 + O2 (g)

Hopefully the reaction will be fast enough for you to see the tiny bubbles. Or, perform the reaction in a plastic bottle, which you have indented to allow for a pressure expansion. You could also use a match to visually confirm oxygen.
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[*] posted on 12-6-2011 at 13:38


Quote: Originally posted by AJKOER  
2 HClO + 2 Cu --> CuCl2.Cu(OH)2

Or,

4 HClO + 2 Cu2O --> 2 CuCl2.Cu(OH)2 + O2 (g)



You have any evidence for this? Or are you just writing pretty and balanced equations?
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