Determining catalyst activation energy (Ea), when moles (M) and temperature (k) are identical.
I'm not sure if this belongs in this forum or the beginners forum, but I am presenting this question for the mathematically inclined to respond.
I am having a discussion about how the chemical activation energy for a catalyst to initiate a transition state is determined when concentration and
temperature are identical.
I am aware of how to identify the reaction rate law, rate law constant, activation energy and frequency factor, and I also know the calculation for
measuring the effect of a catalyst (e*-Ea/RT), however I am having trouble trying to identify how I determine the Ea for the catalytic reaction (kJ
mol-1) in order to plug it in to the equation, when concentration and temperature are identical to the non catalytic reaction.
I have a feeling I am overlooking something very obvious.
Any ideas?
[Edited on 11-7-2020 by Eddie Current]
[Edited on 11-7-2020 by Eddie Current]
[Edited on 11-7-2020 by Eddie Current]
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