metalresearcher
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EQUILIB Web site wrong ??
When filling in on this site
http://www.crct.polymtl.ca/equiweb.php
0oC , 1 atm, 2 mol Al + 0.5 mol Na2CO3
shows
2 Al + 0.5 Na2CO3 =
0.00000 mol gas_ideal
(0.00 C, 1 atm, a=6.5030E-16)
( 6.5030E-16 Na
+ 2.9784E-21 Na2
+ 1.1614E-56 Al
+ 3.1210E-70 Al2O)
+ 0.84211 mol Na_solid
(19.360 gram, 0.84211 mol)
(0.00 C, 1 atm, S1, a=1.0000)
+ 0.38596 mol Al_solid
(10.414 gram, 0.38596 mol)
(0.00 C, 1 atm, S1, a=1.0000)
+ 0.16667 mol Al4C3_solid
(23.993 gram, 0.16667 mol)
(0.00 C, 1 atm, S1, a=1.0000)
+ 7.8947E-02 mol Na2Al12O19_beta2-alumina
(53.191 gram, 7.8947E-02 mol)
(0.00 C, 1 atm, S1, a=1.0000)
which tells as much that Na2CO3 reactis with Al metal at room temperature.
Complete nonsense of course.
Normally they produce reliable results but this ????
Does anyone know this site ?
[Edited on 2010-9-21 by metalresearcher]
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DDTea
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I wouldn't call it "complete nonsense." Did you specify which products you were interested in? There's always some equilibrium at play, and it looks
this little applet is calculating a bunch of possible reactions and the theoretical equilibria for them.
Also, are you sure that 0 C is room temperature? 
"In the end the proud scientist or philosopher who cannot be bothered to make his thought accessible has no choice but to retire to the heights in
which dwell the Great Misunderstood and the Great Ignored, there to rail in Olympic superiority at the folly of mankind." - Reginald Kapp.
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metalresearcher
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I am just interested in making Na metal from Na2CO3 + Al metal.
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DDTea
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So the proposed reaction is:
3 Na2CO3 + 2 Al --?--> 6 Na + 3 CO2 + Al2O3 ? Or something like that...
Here's the result I'm getting for 298.15 K and 1 bar, and using a cutoff of 1e-5:
T = 298.15 K
P = 1.00000E+00 bar
V = 0.00000E+00 dm3
EQUIL. AMOUNT (mol):
NaAlO2_solid-a(s) 2.0000
C_graphite(s) 1.5000
Na2CO3_solid_a(s) 1.5000
Na2O_solid-a(s) 0.5000
So, it's predicting that some reaction happens, just not the one you were thinking of
This is kind of a cool site, but it's not doing what I'd like it to do (i.e.: for given reactants and products, give me the equilibrium data).
"In the end the proud scientist or philosopher who cannot be bothered to make his thought accessible has no choice but to retire to the heights in
which dwell the Great Misunderstood and the Great Ignored, there to rail in Olympic superiority at the folly of mankind." - Reginald Kapp.
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Rogeryermaw
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this is something i was interested in as well but i thought that this reaction would not run because sodium is higher on the reactivity series than
aluminum.
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