Nernst
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Mannich reaction
I'm performing a mannich reaction and therefore I have to place dimethylamine.HCl and paraformaldehyde in my flask. I work with isopropylalcohol as a
solvent. After these additions I place my keton in the flask followed by the addition of HCl.
Now I'm worried about the forming of bis(chloro)methylether. How big is the chance that there will form some bis(chloro)methylether out of
paraformaldehyde and HCl?
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chemrox
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I just looked up an example that used the amine salt and I don't see an issue otherwise. I haven't used paraformaldehyde for this before. How is it
unpoly'd in this case? Ah, I see numerous examples where it is used and it simply dissovles in the solvent system.
[Edited on 16-2-2009 by chemrox]
"When you let the dumbasses vote you end up with populism followed by autocracy and getting back is a bitch." Plato (sort of)
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Nicodem
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Quote: | Originally posted by Nernst
Now I'm worried about the forming of bis(chloro)methylether. How big is the chance that there will form some bis(chloro)methylether out of
paraformaldehyde and HCl? |
You don't have to worry about that.
…there is a human touch of the cultist “believer” in every theorist that he must struggle against as being
unworthy of the scientist. Some of the greatest men of science have publicly repudiated a theory which earlier they hotly defended. In this lies their
scientific temper, not in the scientific defense of the theory. - Weston La Barre (Ghost Dance, 1972)
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rodanid88
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Does anyone know, what the mechanism is in this reaction: phenols or catechol react with formaldehyde and with primary or secondary amine. I know the
first step is that you get the iminium ion, but after that? Probably it will do an electrophilic attack to the aromatic ring, but how?
Thanks
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