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Author: Subject: AlCl3 by double displacement?
Rainwater
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[*] posted on 24-11-2022 at 04:28


Smoking a bird board and half lit wishing i had packed some tubes and a retort

Somewhere it was asked what other salts could be used
Heres some thermodynamics values. Took longer to format this table than to do the math
Code:
Name ΔG ΔH ΔS ΔG = 0 when T = AuCl3 -557.97 -466.90 333.38 -1673.66 C BCl -941.25 -1033 -335.85 2802.59 C BCl3 -180.69 -157.32 85.56 -2111.78 C BrCl -317.57 -292.78 90.73 -3500.13 C CdCl2 -100.46 3.72 381.41 -263.39 C CoCl2 -322.77 -231.38 334.59 -964.66 C CrCl2 -63.94 17.15 296.88 -215.37 C CuCl2 -646.28 -551.45 347.18 -1861.5 C FeCl2 -225.57 -143.64 299.95 -752.02 C FeCl3 -231.73 -185.02 171.00 -1355.12 C HCl -286.00 -308.00 -78.00 3647.0 HgCl2 -595.09 -496.22 361.96 -1644.09 C MnCl2 189 275 313 604.24 C NH4Cl 8.71 220.00 775.00 11.2 NiCl2 -353.70 -253.01 368.61 -959.55 C PbCl2 -188.67 -90.79 358.32 -526.54 C S2Cl2 -804.76 -723.41 297.82 -2702.2 C SnCl4 -946.98 -804.16 522.83 -1811.24 C ZnCl2 -25.39 76.15 371.75 -68.31 C

EDIT:
I edited the list of all the compounds that wouldn't provide a negative delta g with a temp less than 1000c
Looks like the reactions that have reported low yields or difficulty in reproduceling are endothermic.

[Edited on 24-11-2022 by Rainwater]




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[*] posted on 24-11-2022 at 07:29


Quote: Originally posted by Rainwater  


Looks like the reactions that have reported low yields or difficulty in reproduceling are endothermic.



Thanks for these values.

Have you taken into account the entropic effect of AlCl3(g)?

[Edited on 24-11-2022 by blogfast25]




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[*] posted on 24-11-2022 at 09:51


Quote: Originally posted by blogfast25  

Have you taken into account the entropic effect of AlCl3(g)?

I am not sure what that is so I'm gonna say no.

When I was first reading this thread, not understanding the difficulty in creating the product, it lead to some nice googling, lots of concepts in play.

Those values were generated using the formula ΔG = ΔH - TΔS
Thermodynamic values are from here

The listed values were from reagents, anhydrous, in solid state unless data for solids was not available, at 1 atm, 0c. (Probley got the state wrong for some of those)

"ΔG=0 T=" is formed by reworking the equation to solve for t when delta g is zero

If ΔG =0; T = ΔH ÷ ΔS
No other considerations were used when generating that data.

Ramble:
I have been studying this equation for a few months and im still learning how it is used and properly applied.
Constructive criticism is welcome.

Any reading recommendations are greatly appreciated.
My current textbook isChemistry 2e by OpenStax (I like free)

I assume that when ΔG is below zero,
the chemical equilibrium will favor products.

Then by educated guessing and limited understanding, I compare the delta g of various arrangements, assuming that the probability of product formation is somehow related to the difference in delta g, the more negative delta g, the more likely the arrangement is to form. I have not found an example yet where this is not true.
I suspect this will change when I begin to learn about organic reactions.




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[*] posted on 24-11-2022 at 10:39


Quote: Originally posted by Rainwater  

I am not sure what that is so I'm gonna say no.

When I was first reading this thread, not understanding the difficulty in creating the product, it lead to some nice googling, lots of concepts in play.

Those values were generated using the formula ΔG = ΔH - TΔS
Thermodynamic values are from here

The listed values were from reagents, anhydrous, in solid state unless data for solids was not available, at 1 atm, 0c. (Probley got the state wrong for some of those)

"ΔG=0 T=" is formed by reworking the equation to solve for t when delta g is zero

If ΔG =0; T = ΔH ÷ ΔS
No other considerations were used when generating that data.

Ramble:
I have been studying this equation for a few months and im still learning how it is used and properly applied.
Constructive criticism is welcome.

Any reading recommendations are greatly appreciated.
My current textbook isChemistry 2e by OpenStax (I like free)

I assume that when ΔG is below zero,
the chemical equilibrium will favor products.

Then by educated guessing and limited understanding, I compare the delta g of various arrangements, assuming that the probability of product formation is somehow related to the difference in delta g, the more negative delta g, the more likely the arrangement is to form. I have not found an example yet where this is not true.
I suspect this will change when I begin to learn about organic reactions.


As an 'educator' I can only be glad to see someone studying the subject!

A few points.

ΔGreaction < 0 is not a sufficient condition for the reaction to proceed because themodynamics makes no pronouncements about kinetics.

For the combustion of coal the ΔGreaction is very negative, yet the reaction does not proceed at RT, only after heating. There are tonnes of examples like that.

Entropy: for gases and vapours the ΔS is much higher than lliquids or solids. This helps with the negativity of ΔGreaction, so that effect should be taken into account.

The reaction:

$$\text{CsCl}(s) + \text{Li}(l) \to \text{Cs}(g)+\text{LiCl}(l)$$

carried out at high(ish) temperature and high vacuum proceeds, with gaseous Cs being distilled off. The ΔGreaction the way you calculate it would be positive.

http://www.sciencemadness.org/talk/viewthread.php?tid=6981 (2nd page)

Another exqmple is the silicothermic reduction of magnesia (see Wikipedia)

https://en.wikipedia.org/wiki/Magnesium#Production



[Edited on 24-11-2022 by blogfast25]




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[*] posted on 9-12-2022 at 13:16


Got the AgCl drying covered on a watchglass heated to 110c,
cleaned my glass, took off my gloves balled them up and damn!!! I hate silver nitrate

Soon as its dry and the rain lets up im gonna load a sample into a test tube and add some aluminum.
Should be soon




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[*] posted on 9-12-2022 at 13:37


On further consideration, CuCl should give a much less exothermic process than CuCl2. And it's insoluble.



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[*] posted on 9-12-2022 at 13:39


Quote: Originally posted by clearly_not_atara  
On further consideration, CuCl should give a much less exothermic process than CuCl2. And it's insoluble.


And it's not so easy to make.




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[*] posted on 9-12-2022 at 13:45


Quote: Originally posted by Rainwater  
Got the AgCl drying covered on a watchglass heated to 110c,

Soon as its dry and the rain lets up im gonna load a sample into a test tube and add some aluminum.
Should be soon


Note that some Cl would not be proof,but it would be evidence...

Try also to sublime at 180 C the suspected AlCl3.




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[*] posted on 9-12-2022 at 13:49


Acc. 'plante' you can make TiCl4 by heating titania with potassium pyrosulphate and NaCl. I wonder if something similar might work for AlCl3?



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[*] posted on 9-12-2022 at 16:18


So 3.42g of AgCl. Slightly discolored was my yield.

0.11g Al alloy 6061 was filled and placed into a dry borosilicate tube, closed at 1 end.(dont laugh, my first attempt at glass work. Youtube makes it look too easy)

To this ummm.... math ... . Need 1.75g AgCl
0.41g of AgCl where added.
Reagents were crushed and mixed inside the tube.
Tube heated. Reaction witnessed.
This may produce AlCl3 but your not gonna want to do it in a lab

All contents are contained within the test tube.
Edit #3 i got to read stuff better
Edit #2:
theories,
1) the fine aluminum powder increased the reaction rate too much.
2) the aluminum reacted with oxygen in the tube

Edit #1: added pictures and video
https://youtu.be/Rvq3LjHJvsM

20221209_174644.jpg - 2.3MB 20221209_180517.jpg - 2.2MB 20221209_182513.jpg - 1.2MB 20221209_182947.jpg - 1.3MB

[Edited on 10-12-2022 by Rainwater]

[Edited on 10-12-2022 by Rainwater]

[Edited on 10-12-2022 by Rainwater]




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[*] posted on 9-12-2022 at 17:28


Quote: Originally posted by Rainwater  

This may produce AlCl3 but your not gonna want to do it in a lab



So you're trying 3 AgCl + Al ?









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[*] posted on 9-12-2022 at 17:53


Ya
$$Al + 3AgCl \rightarrow AlCl_3 + 3Ag$$

[Edited on 10-12-2022 by Rainwater]




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[*] posted on 10-12-2022 at 00:40


Wouldn't PbCl2 be ideal?
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[*] posted on 10-12-2022 at 01:02


Quote:
Wouldn't PbCl2 be ideal?

Thermodynamics indicates that lead would be less energetic, another easily sourced metal and easily converted into chloride salt but toxic. It is easy to make anhydrous, melting point is similar. Should work.
Lets find out.

I'm gonna use up the rest of my AgCl, then ill try Pb.
I want a better way to refine silver than lye and sugar.




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[*] posted on 10-12-2022 at 02:50


Here are my notes so far very promising
im not sure how to proceed with extraction and further testing.

Attachment: Alcl3 test_221210_054706.pdf (282kB)
This file has been downloaded 207 times





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[*] posted on 10-12-2022 at 08:16


Quote: Originally posted by Rainwater  

I want a better way to refine silver than lye and sugar.


Hmmm... most people would give their right hand to recover a metal with just sucrose and lye and no heat, you know? :D

[Edited on 10-12-2022 by blogfast25]




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[*] posted on 10-12-2022 at 10:22


I wonder if anyone skilled in the use of reaction heat calculators could look at the double decomposition of sodium chloride and aluminium sulphide for me.
I have a hunch that the AlCl3 would distil out.

If it does then there's an interesting possibility of providing the heat for the reaction from a mixture of Al, NaCl and S8.
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[*] posted on 10-12-2022 at 10:54


Quote: Originally posted by unionised  
I wonder if anyone skilled in the use of reaction heat calculators could look at the double decomposition of sodium chloride and aluminium sulphide for me.
I have a hunch that the AlCl3 would distil out.

If it does then there's an interesting possibility of providing the heat for the reaction from a mixture of Al, NaCl and S8.


Al2S3 is one of the stinkiest things I've ever made, it's incredibly sensitive to moisture and water.

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[*] posted on 14-12-2022 at 06:59


Based on the table that Rainwater provided, ammonium chloride looks like the easiest chloride to use for substitution. I don't have any an the moment, but as soon as I can get some, I plan to try that reaction. Another benefit is that all of the side products are gasses, so recovering the aluminium chloride should be easy.
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[*] posted on 14-12-2022 at 07:59


I am certain that AlCl3 forms a complex with NH3. Not sure how easy it is to break — maybe just TsOH will do it, but maybe it's intractable.



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[*] posted on 14-12-2022 at 08:20


If you could get the salt anhydrous, that stuff is difficult to dry and keep dry. Post some experiments and let us know what you discover.



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[*] posted on 14-12-2022 at 09:50


Quote: Originally posted by Rainwater  
If you could get the salt anhydrous, that stuff is difficult to dry and keep dry. Post some experiments and let us know what you discover.


I don't think moist AlCl3 can be desiccated: once moist the hydrolysis damage has already been done and is irreversible.

But preparing very dry AlCl3 is only a matter of starting from very dry precursors.

[Edited on 14-12-2022 by blogfast25]




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[*] posted on 14-12-2022 at 10:59


Sorry, my last post was ambiguous, I meant the ammonia chloride salt. It is reported hygroscopic, heating it above to 300c will dry it out good.
At 337c(wiki) it decomposes but upon cooling will reform.
During my test it was nessacery to have a liquid reagent, in my case that was aluminum metal.
After some quick reading, it appears anhydrous ammonia does not react with aluminum.
Ill look through my reagents, i should have some NH3Cl and see if it works.

After doing some reading, looks like under anhydrous conditions ammonia + aluminum trichloride does form a complex, but google isnt turning up much information




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[*] posted on 14-12-2022 at 14:51


Another win. Not proven to be AlCl3 but this time the reaction was easily controlled. Next time i will use an excess of aluminum.

The reaction tube was cleaned and flame dried
0.55g of NH3Cl was added to the tube.
The tube was heated until the steam stopped coming off and the salt began to condense up the tube.
0.07g of aluminum foil was pushed to the bottom of the tube until it was touching the solid ammonia chloride.
The mixture was heated until it began to melt. White smoke formed with the smell of HCl.l and condensed on the cooler parts of the tube
The mixture was kept just above the melting point with a torch until no more smoke appeared.
The apparatus was allowed to cool. All the white precipitate was scrapped off the sides of the tube into the bottom of the tube.

Upon heating, the solid migrated back up the tube with no visible liquid.
I placed a titanium rod, 3mm in diameter inside the tube as I heated it. A white powder formed on the rod.
When I dropped water down the rod, it contacted the white solid.

Dramatic pause...

Click here to see the results




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[*] posted on 14-12-2022 at 14:59


I think there is something wrong with the link.
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