Answer is nitronic acid rearangement!
CH3-C(OH)=C(CH3)-NO2 <--> CH3-CO-CH(CH3)-NO2
CH3-CO-CH(CH3)-NO2 <-OH(-)-> CH3-CO-C(CH3)=N(O)-OH
Thus beta nitro enols undergo enol-ceton [ketone] equilibrium to provide a alfa hydrogenated nitro derivative in tiny % that gives the yellow colour;
the later upon the action of a base undergo the nitronic rearangement
cf NM:
CH3-NO2 + NaOH --> CH2-NO2(-) + Na(+) --> CH2=N(O)-ONa
The later compound is deep orange to deep red-brown! |